Ex 10
AB=0,75xBC AB=(3/4)BC
10²=BC²+(3BC/4)² 100=BC²+(9/16)xBC² x 16
1600=16BC²+9BC² 1600=25BC²
BC²=1600/25=64 BC=√64=8 cm
AB²=10²-BC² AB²=10²-8²=100-64=36 AB=√36=6 cm
Perimetru=6x2 + 8x2=12+16=28 cm
Ex 11
diagonalele²=8²+6²=64+36=100 diagonalele=√100=10 cm
Ex 12
diagonala=latura x √2 <=> latura=12√2 / √2=12 cm
Perimetrul=12cm x 4=48cm
Ex 13
BP=AB-AP=10 cm-4cm=6cm
BQ=BC-CQ=3cm-2cm=1cm ΔPBQ e dreptunghic
PQ²=6²+1²=36+1=37
PQ=√37 cm
