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Descompuneti in factori :
i) (x+3)²+2(x+3)+1
j) (2x-5)²-4(2x-5)+4


Răspuns :

i) (x+3)²+2(x+3)+1=x²+6x+9+2x+6+1=x²+8x+16
j) (2x-5)²-4(2x-5)+4=4x²-20x+25-8x+20+4=4x²-28x+49