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Descompuneti in factori : 9x²-6x(y+2)+(y+2)²=
( x²+y²-z²)²-4x²y²=


Răspuns :

9x²-6x(y+2)+(y+2)²=[3x-(y+2)]²=(3x-y-2)²

( x²+y²-z²)²-4x²y²=(x²+y²-z²-2xy)(x²+y²-z²+2xy)=
=[(x-y)²-z²][(x+y)²-z²]=(x-y-z)(x-y+z)(x+y-z)(x+y+z)