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rezolvati
3 supra a+2supra a+11 supra a
si 2x supra y+7x supra y+11x supra y


Răspuns :

[tex] \frac{3}{a} + \frac{2}{a} + \frac{11}{a} = \frac{3+2+11}{a} = \frac{16}{a} [/tex]

[tex] \frac{2x}{y} + \frac{7x}{y} + \frac{11x}{y} = \frac{2x+7x+11x}{y} = \frac{20x}{y} [/tex]