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suma a 4 nr. consecutive este 42.care sunt cele 4 nr?

Răspuns :

a+(a+1)+(a+2)+(a+3)=42
a+a+1+a+2+a+3=42
4a=42-6=36
a=36:4=9
a=9
a+1=10
a+2=11
a+3=12
a+a+1+a+2+a+3=42
4a+6=42
4a=42-6
4a=36
a=36:4
a=9(I nr)
9+1=10(II nr)
9+2=11(III nr)
9+3=12(IVnr)