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Determinati numerele a,b,c € Q invers proportionale cu nr 4,16,27 stiind ca AxBxB = 1

Răspuns :

[tex]4a+16b=27c=k\Rightarrow a=k/4;\ b=k/16;\ c=k/27[/tex]

[tex]abc=1\Rightarrow \dfrac k4\cdot\dfrac{k}{16}\cdot\dfrac{k}{27}=1\Rightarrow k^3=4^3\cdot3^3\Rightarrow k=12[/tex]  Deci:

[tex]a=3;\ b=\dfrac34; \ c=\dfrac49[/tex]