[tex] \sqrt{ \frac{1}{4} } + \sqrt{ \frac{1}{9} } + \sqrt{ \frac{49}{36} } = \frac{ \sqrt{1} }{ \sqrt{4} } + \frac{ \sqrt{1} }{ \sqrt{9} } + \frac{ \sqrt{49} }{ \sqrt{36} } = \frac{1}{2} + \frac{1}{3} + \frac{7}{6} = \frac{3}{6}+ \frac{2}{6} + \frac{7}{6} = [/tex][tex] \frac{3+2+7}{6} = \frac{12}{6} =2[/tex]