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Dau COROANA!!!
In trapezul ABCD, AB paralel DC AB=120cm BC=45 cm AD=DC=60 cm.Notand AD intersectat BC ={P} Sa se afle perimetru triunghiului PAB?


Răspuns :

DCparalelcuAB⇒∧PDC≈∧PAB⇒PD/PA=PC/PB=DC/AB⇔PC/PC+45=1/2(60/120=DC)⇒  2PC=PC+45⇒PC=45CM
PD/PD+60=1/2⇒ 2PD=PD+60⇒ PD=60CM
PA=PD+DA=120
PB=PC+BC=90
P∧PAB=PA+PB+AB=120+90+120=330CM.
Sper ca te-am ajutat!Coroana???