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∛(x+1)+∛(3x+1)=∛(x-1), x=?

Răspuns :

     
[tex] \sqrt[3]{x+1}+ \sqrt[3]{x+1}=\sqrt[3]{x-1} \\ \\ 2\sqrt[3]{x+1}=\sqrt[3]{x-1} \\ \\ \text{Ridicam ecuatia la puterea a 3-a} \\ \\ 8(x+1)=x-1 \\ 8x+8=x-1 \\ 8x-x=-1-8 \\ 7x=-9 \\ x= \frac{-9}{7} [/tex]