[tex]x-( \frac{1}{2}x-1)- \frac{1}{3}( \frac{1}{2}x+1)-5=29 [/tex]
[tex]x- \frac{1}{2}x+1- \frac{1}{6}x- \frac{1}{3}-5=29 [/tex]
amplificam x, 1, 5 si 29 cu 6... 1/2x cu 3 si 1/3 cu 2 ptu a aduce la acelasi numitor
6x-3x+6-x-2-30=174
6x-3x-x=174+30+2-6
2x=200
x=200:2
x=100
Matei initial avea 100 lei