Fie [tex]p= \frac{AB+BC+AC}{2}= \frac{36}{2}=18 [/tex].
[tex]A= \sqrt{p(p-AB)(p-BC)(p-AC)}= \sqrt{18*5*5*8}= [/tex][tex]= \sqrt{2*9*5*5*8}= \sqrt{ 3^{2}* 5^{2}*16 }=3*5*4=60 ( cm^{2} ) [/tex]
[tex]A= \frac{ h_{AC}*AC }{2}=> h_{AC}= \frac{2A}{AC}= \frac{120}{10}=12(cm). [/tex]
[tex]A= \frac{ h_{AB}*AB }{2}=> h_{AB}= \frac{2A}{AB}= \frac{120}{13} (cm) [/tex]
[tex] h_{BC}= h_{AC}= \frac{120}{13} [/tex](cm).
