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afla trei nrpare consecutive,din a caror suma daca scazi suma nr impare consecutivece se afla intre ele ,obtii 12


Răspuns :

[(a+2)+(a+4)+(a+6)]-[(a+1)+(a+3)+(a+5)]=12
(a+2+a+4+a+6)-(a+1+a+3+a+5)=
3a+12-3a-9=3