y(x-2) + 3x = 13y(x-2)=13-3x
y=(13-3x)/(x-2)
[tex]y= \frac{-3(x-2)+7}{x-2} =\frac{-3(x-2)}{x-2} +\frac{7}{x-2} =-3+\frac{7}{x-2} \\
\frac{7}{x-2} \in Z=>(x-2)\in\{\pm1;\pm7\}\\
x-2=-1=>x=1=>y=-10\\
x-2=1=>x=3=>y=4\\
x-2=-7=>x=-5=>y=-4\\
x-2=7=>x=9=>y=-2[/tex]