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Răspuns :

[tex] 4^{n}- 2^{2n+1}+1 = (2^{n})^{2}-2* 2^{n}*1+ 1^{2} = ( 2^{n}-1)^{2} [/tex] -patrat perfect.

*Am aplicat formula [tex](a-b)^{2}= a^{2}-2ab+ b^{2} [/tex].
=2^2n-2^2nx2+1=
=2^2n(1-2)+1=
=-2^2n+1 este patrat perfect