perimetrul triunghiului echilateral = 3* L => L= 36:3 = 12cm
daca AB||NP => doua egalitati:
1)
[tex] \frac{AM}{MN} = \frac{MB}{MP} \\ \frac{4}{12} = \frac{MB}{12} \\ MB=4cm[/tex]
2)
[tex]\frac{AM}{MN} = \frac{AB}{NP} \\ \frac{4}{12} = \frac{AB}{12} \\ AB=4cm [/tex]
AN=BQ=MN-AM-12-4=8cm
Perimetrul patrulaterului ABPN = AB+AN+BP+NP = 4+4+4+12 = 24 cm