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aflati DVA a ecuatiilor:
a)[tex] \frac{2-x}{x}=3[/tex]
b)[tex] x^{2} -1=0[/tex]
c)[tex] \sqrt{x} +2=6[/tex]
d)3x+5=x+1



Răspuns :

a. 2 supra x minus x supra x = 3 <=> 2 supra x minus 1 = 3 <=> 2 supra x = 2 => x=1
b. [tex] x^{2} [/tex] - 1=0 <=> [tex] x^{2} [/tex]=1 => x=1
c. [tex] \sqrt{x} [/tex] = 4 => x=2
d. 3x-x = 6 => x=2. 
Cu placere.