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Cum se rezolva :
x² + 4x + 3 = ?


Răspuns :

x2+4x+3 = 0
a=1 b=4 c=3
Δ=16-12=4
x1=(-4-2)/2 = -6/2=-3
x2=(-4+2)/2=-2/2=-1
S={-1;-3}
delta b patrat -4ac--> 4 la patrat -4ori1ori3
=16-12
delta=4
 x1,x2=(-4+-2)2
x1=-3
x2=-1