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Calculati: e) 3+6x[30+6x(3+5x6)-28]-3   f) 2+2x[2+3x(2+202:2-306:3)]       Macar unul

Răspuns :

e)3+6x[30+6x(3+30)-28]-3=
=3+6x[30+6x33-28]-3=
=3+6x[30+198-28]-3=
=3+6x[30+170]-3=
=3+6x200-3=
=3+1200-3=
=3+1197=
=1200