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Afla nr.de moli de atomi de fier, continuti in 93 g fosfor; dar in 93 kg fosfor?

Răspuns :

1mol.......................31g P
x moli.....................93g P
x=93*1/31=3moli P

93kg=93000g
1mol............................31g P
y moli...........................93000g P
y=93000*1/31=3000g=3kg P