👤

Ce volum ocupa,la 327 de grade celsius si 300atm,2800kg azot molecular?imi trebui urgent:(



Răspuns :

2800 kg N2 = 100 kmoli
pV=nr moli * R * T (327+273)
=>V= nr moli * R * T / p
V=100 * 0,082 * 600/300=> V = 16,4 m cubi