1 mol Ca.............35g
x.........................14,2g
x=14,2/35=0,40 moli
1mol.................6,023 * [tex] 10^{23} [/tex] atomi
0,40 moli...................x
x=0,40* 6,023 * [tex] 10^{23} [/tex]=2,409 * [tex] 10^{23} [/tex] atomi
nr de e =40* 2,409* [tex] 10^{23} [/tex]