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[tex] \frac{x-1}{2} + \frac{x+4}{6} +5= \frac{x}{12} [/tex]  Ceva ajutor ?:D. 



Răspuns :

(x-1)/2 +(x+4)/6+5=x/12
1) numitorul comun
6(x-1)+2(x+4)+5·12=x
6x-6+2x+8+60=x
6x+2x-x=-60-8+6
7x=-62
x=(-62)/7=-8 intrgei si 6/7