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(3+6+9+......+30)-(2+4+6+.....+20)

Răspuns :

(3+6+9+...+30)-(2+4+6+...+20)= 3 x (1+2+3+...+10) - 2 x (1+2+3+...+10)=
(3-2) x (1+2+3+4+...+10) = 1+2+3+4+...+10= 55
[tex](3+6+9+....+30)=3(1+2+3+....+10)= \frac{330}{2}=\boxed{165}\\\\ (2+4+6+....+20)=2(1+2+3+.....+10)=\frac{220}{2}=\boxed{110}\\\\ \boxed{165-110=55}.[/tex]