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Calculati mas. Mas <-lor D si A invers proportionale cu 1,(6) si 2,5.

Răspuns :

 [tex]1,(6)=\frac{16-1}{9}=15 / 9 = 5 / 3\;;\\
2,5=\frac{25}{10}=\frac{5}{2} \;;\\
\frac{D}{3/5}=\frac{A}{2/5}\; \\
\rightarrow\;\;D\cdot\frac{2}{5}=A\cdot\frac{3}{5}\;|_{\cdot5}\\
deci \;\;2 \,D=3\, A \;mai\;departe\; lipsesc\;date \;...[/tex]