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Aflati 2 numere stiind ca au suma 402,iar daca ale impartim obtinem catul 5 si restul 18

Răspuns :

a+b=402
a:b=5r18
a=5b+18
5b+18=b=402
6b+18=402
6b=384
b=384:6
b=64
a+64=402
a=402-64
a=338
I = x II = 5 x + 18 I+ II = 402 x+ 5 x+ 18= 402 6 x +18= 402 6 x=402-18 6x= 384 x =384:6 x=64( I) 64*5+18=320+18= 338 ( II )