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a+d3+c=41 , b-a=5, a-c=5, aflați a, b, c

Răspuns :

a + b + c = 41
b = a + 5
c = a - 5
a + a + 5 + a - 5 = 41
3a = 41
a = 41 : 3
a = 13,(6)
b = 13,(6) + 5
b = 18,(6)
c = 13,(6) - 5
c = 8,(6)
a+b+c=41
b-a=5
a-c=5
a=5+c
b=5+a
5+c+5+a+c=41
10+2c+a=41
10+2c+5+c=41
15+3c=41
3c=26⇒c=8.66
a=5+8.66=13.66
b=5+13.66=18.66