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Inversul  lui  3 - 2√2 este ...

Răspuns :

[tex]\dfrac{1}{3-2\sqrt2}=\dfrac{3+2\sqrt2}{(3-2\sqrt2)(3+2\sqrt2)}=[/tex]

[tex]=\dfrac{3+2\sqrt2}{3^2-(2\sqrt2)^2}=\dfrac{3+2\sqrt2}{9-8}=3+2\sqrt2[/tex]