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1)5√2 comparat cu 2√6
2)Solutia reala a ecuatiei 2x+7=-5 


Răspuns :

 [tex] 1).\;5\sqrt2\; =\sqrt{5^2\cdot2}=\sqrt{50}\;;\\ 2\sqrt6=\sqrt{2^2\cdot6}=\sqrt{24}\;;\;\rightarrow\;\sqrt{50}>\sqrt{24}\;;\\ 2).\;2x+7=-5\;\rightarrow\;2x=-5-7\;;\;\\ x=-12:2=-6 [/tex]