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9^5-(3^5)^2+8^4-(2^4)^3



Răspuns :

(3^2)^5-3^10+(2^3)^4-(2^3)^4=

3^10-3^10+2^12-2^12=

0+2^12-2^12=0

=0


(3^2)^5-3^10+(2^3)^4-(2^3)^4 AICI AM  DESCOMPUS PE  9 SI 8 2^12 IAR RESTUL LE-AM CALCULAT 
3^10-3^10+2^12+2^12
 0-2^12-2^12
0
CEL MAI INTELIGENT RASPUNS