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Raportul masurilor a 2unghiuri complementare este de 1pe2 . Determinatimasura unghiului mai mare

Răspuns :

[tex]\frac{a}{b}=\frac{1}{2} \\\\ \boxed{2a=b} \\\\ a+b=90^0 \\\\ a+2a=90^0 \\\\ 3a=90^0 \ |:3 \\\\ \boxed{\boxed{a=30^0}} \\\\\\ b=2*30^0 \\\\ \boxed{\boxed{b=60^0}}[/tex]