a+b+c=68
[tex] \frac{a}{4}= \frac{b}{5}= \frac{c}{8} = \frac{a+b+c}{4+5+8}= \frac{68}{17} =4[/tex]
[tex] \frac{a}{4}=4 => a=16 \\ \frac{b}{5}=4 => b=20 \\ \frac{c}{8}=4 =>c=32 [/tex]
Solutie: 16,20,32
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77=a+b+c
[tex] \frac{a}{ \frac{1}{2} } = \frac{b}{ \frac{1}{4} } = \frac{c}{ \frac{1}{6} }= \frac{a+b+c}{ \frac{1}{2}+ \frac{1}{4}+ \frac{1}{6} } = \frac{77}{ \frac{6+3+2}{12} }= \frac{77}{ \frac{11}{12} }=77* \frac{12}{11} =84[/tex]
[tex] \frac{a}{ \frac{1}{2} }=84 => a=84* \frac{1}{2} =42 [/tex]
[tex] \frac{b}{ \frac{1}{4} }=84 => b=84* \frac{1}{4}=21 [/tex]
[tex] \frac{c}{ \frac{1}{6} } =84 => c=84* \frac{1}{6}=14 [/tex]
Solutie: 42,21,14
