a.AE=4 cm
AB=16 cm
AC=20 cm
FC=15 cm
AF=AC-FC
AF=20-15=5 cm
[tex] \frac{AE}{AB} = \frac{AF}{AC} [/tex] ⇒ [tex] \frac{4}{16} = \frac{5}{20} [/tex] ⇒ [tex] \frac{1}{4} = \frac{1}{4} [/tex] *simplificam la prima cu 4,iar la a doua cu 5*
⇒*teorema reciproca a lui Thales* EF II BC
b.AB=28 cm
EB=21 cm
AF=6 cm
FC=18 cm
AE=AB-EB
AE=28-21=7 cm
[tex] \frac{AE}{EB} = \frac{AF}{FC} [/tex] ⇒ [tex] \frac{7}{21} = \frac{6}{18} [/tex] ⇒ [tex] \frac{1}{3} = \frac{1}{3} [/tex] *simplificam la prima cu 7 ,iar la a doua cu 6* ⇒*teorema reciproca a lui Thales* EF II BC
