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Fie un triunghi ABC cu AB=42mm si AC=63mm si punctele D∈(AB, E∈(AC.Stabiliti daca DE||BC , stiind ca:
AD=5,2mm si EC=1,5mm si C∈(AE)
Multumesc!!!


Răspuns :

BD=AB-AD=42-5,2=36,8 (mm)
AE=AC-CE=63-1,5=61,5 (mm)

[tex] \frac{AD}{BD} [/tex]=[tex] \frac{5,2}{36,8} = \frac{52}{368} = \frac{13}{92} [/tex]
[tex] \frac{AE}{CE} = \frac{61,5}{1,5} = \frac{615}{15} = 41[/tex]

Cum [tex] \frac{13}{92} \neq 41 => \frac{AD}{BD} \neq \frac{AE}{CE} [/tex] => DE nu e paralel cu BC.


Vezi imaginea ALBASTRUVERDE12