a)∛(x+2)=3∛(x-1) ridicam la cub
x+2=27(x-1)
x+2=27x-27
26x=29
x=29/26
b) ∛(x-1)+∛(2x+1)=0
∛(x-1)=-∛(2x+1) ridicam la cub
x-1 = - (2x+1)
x-1=-2x-1
x=0
d) ∛(x²-x+1)+∛(2x-3)=0
∛(x²-x+1)=-∛(2x-3) ridicam la cub
x²-x+1=-(2x-3)
x²-x+1=-2x+3
x²+x-2=0
x²-1+x-1=0
(x-1)(x+1)+(x-1)=0
(x-1)(x+1+1)=0
(x-1)(x+2)=0
x-1=0 ⇒x=1
x+2=0 ⇒ x=-2
c)∛(1-x)=√(x-1) ridicam la cub
1-x= √(x-1)√(x-1)√(x-1)
1-x=(x-1)√(x-1)
x=1
