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Calculati :
a)√6·√2=
c)√9·√45= 


Răspuns :

a) √6 ·√2 =√12=2√3
b)√9·√45= 3·3√5=9√5
a)[tex] \sqrt{6} * \sqrt{2} = \sqrt{12} [/tex]=[tex] \sqrt{4} * \sqrt{3} = 2\sqrt{3} [/tex]

b)[tex] \sqrt{9} * \sqrt{45}=3* \sqrt{9} * \sqrt{5} [/tex]= [tex]3*3* \sqrt{5} =9 \sqrt{5} [/tex]

c)2[tex] \sqrt{3} (3 \sqrt{3} + \sqrt{2} )+ \sqrt{2}(5 \sqrt{2} - \sqrt{3})= 6 \sqrt{3}^{2} + 2\sqrt{6} +5 \sqrt{2}^{2} - \sqrt{6} [/tex]

=6*3+5*2+[tex] \sqrt{6} [/tex]=9+10+[tex] \sqrt{6} [/tex]=19+[tex] \sqrt{6} [/tex]