D ∈ AB
=> AD + BD = AB
PΔACD = AC + CD + AD = 11 cm
PΔBCD = BC + CD + BD = 9 cm
PΔABC = AB + BC + AC = 14 cm
Adunam perimetrele triunghiurilor ΔACD si ΔBCD.
ΔACD + ΔBCD = 11 + 9
(AC + CD + AD) + (BC + CD + BD) = 20 cm
AC + BC + (CD + CD) + (AD + BD) = 20 (dar AD + BD = AB )
AC + BC + AB + 2×CD = 20 cm (dar AC + BC + AB = PΔABC )
PΔABC + 2 × CD = 20 cm (dar PΔABC = 14 cm)
14 cm + 2 × CD = 20 cm
2 × CD = 20 - 14 cm
2 × CD = 6 cm
CD = 6 / 2 = 3 cm