Prima fractie o amplifici cu [tex] \sqrt{6} -2[/tex] si vei obtine: [tex] \frac{ (\sqrt{6} -2)( \sqrt{6}-2) }{( \sqrt{6} +2)( \sqrt{6}-2) }= \frac{ ( \sqrt{6}-2) ^{2} }{6-4} = \frac{6-4 \sqrt{6}+4 }{2} = \frac{10- 4\sqrt{6} }{2}= \frac{2(5-2 \sqrt{6}) }{2}=5-2 \sqrt{6} [/tex]
Iar la a doua fractie: [tex] \frac{( \sqrt{3} - \sqrt{2} )^2}{2} = \frac{3-2 \sqrt{6}+2 }{2}= \frac{5- 2\sqrt{6} }{2} [/tex]
Dupa ce faci calculele vei obtine ca: [tex] \frac{5-2 \sqrt{6}}{\frac{5- 2\sqrt{6} }{2}} =2[/tex]
