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Simplificati rapoartele si aflati domeniul lor de definitie:
1)x²-2x+1 supra x²-1
2)x²+10x+25 supra x²-25


Răspuns :

[tex] \frac{ x^{2} -2x+1}{ x^{2} -1} = \frac{ (x-1)^{2} }{(x-1)(x+1)} = \frac{x-1}{x+1} [/tex]
[tex] \frac{ x^{2} +10x+25}{ x^{2} -25} = \frac{ (x+5)^{2} }{(x-5)(x+5)} = \frac{x+5}{x-5} [/tex]