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Scrieti nr. 96 ca suma a sase numere impare consecutive

Răspuns :

2n+1+2n+3+2n+5+2n+7+2n+9+2n+11=96
12n+36=96
12n=96-36
12n=60
n=60:12
n=5
 
primul numar: 2*5+1=11
al 2 lea numar 2*5+3=13
al 3 lea numar  2*5+5=15
al 4 lea numar 2*5+7=17
al 5 lea numal 2*5+9=19
al 6 lea numar 2*5+11=21
 
Dem: 11+13+15+17+19+21=96