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Stiind ca x\y=2\3, calculati 6x+y\x+3y .  plizz ajutatima va rog apropo \inseamna ,,pe''



Răspuns :

Una din rezolvari ar fi asa
[tex]\dfrac xy=\dfrac23\Rightarrow x=\dfrac{2y}{3}[/tex]

[tex]\dfrac{6x+y}{x+3y}=\dfrac{6\cdot\dfrac{2y}{3}+y}{\dfrac{2y}{3}+3y}=\dfrac{5y}{\dfrac{11y}{3}}=5\cdot\dfrac{3}{11}=\dfrac{15}{11}[/tex]