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Rezolvati.  a)11*11 la puterea3 >11 la puterea 6+x       b) 25 la puterea18>5 la puterea x+2



Răspuns :

a) 11* 11³ > [tex] 11^{6+x} [/tex] <=> [tex] 11^{4} [/tex] > [tex] 11^{6+x} [/tex] => 4>6+x => x<-2 => x∈{-3,-4,-5...}

b) [tex] 25^{18} > 5^{x+2} [/tex] <=> [tex] 5^{36} [/tex] > [tex] 5^{x+2} [/tex] => 36>x+2 => x<34 => x∈{...-3,-2,-1,0,1,2,...,33}