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Aflati numerele naturale x , stiind ca : ( 2³ + 3 )² + 5² * x ≤ 606 .

Răspuns :

[tex](8+3)^{2} [/tex] +25·x ≤ 606
[tex] 11^{2} [/tex]+25·x ≤ 606 | -121
25·x ≤ 485 | :25
x ≤ 19,4
x∈{19,18...,1,0}
(8+3)^{2}+25x \leq 606 64+2*8*3+9+25x \leq 606 64+48+9+25x \leq 606 121+25x \leq 606 25x \leq 606-121 25x \leq 485 X \leq 19,4 Acel /leq este mai mic sau egal