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DACA 2a+b=150 SI 3b+c=50 atunci numarul 6a+9b+2c este 




Răspuns :

6a+9b+2c=3(2a+b)+2(3b+c)=3*150+2*50=450+100=550
2a+b=150 Ix3
3b+c=50 Ix2
6a+3b=450
6b+2c=100
6a +3b+6b+2c=450+100
6a+9b+2c=550