[tex]a+b=24 \frac{3}{8}[/tex]
[tex]a=3 \frac{5}{6} +b= \frac{6*3+1}{6} +b= \frac{18+5}{6} +b= \frac{23}6} + b[/tex]
[tex]a+b=24 \frac{3}{8}[/tex]
[tex]a+b=\frac{8*24+3}{8}[/tex]
[tex] \frac{23}{6}+b +b=\frac{195}{8}[/tex]
[tex]2b=\frac{195}{8}- \frac{23}{6}[/tex]
[tex]2b= \frac{3*195-4*23}{24}[/tex]
[tex]2b= \frac{585-92}{24}[/tex]
[tex]2b= \frac{493}{24}[/tex]
[tex]b= \frac{493}{24} * \frac{1}{2} = \frac{493}{48}[/tex]
[tex]a= \frac{23}{6} + b= \frac{23}{6} + \frac{493}{48} = \frac{23*8+493}{48} =\frac{184+493}{48}= \frac{677}{48}[/tex]
Verificare
[tex]a+b= \frac{677}{48} + \frac{493}{48} = \frac{677+493}{48} = \frac{1170}{48} = \frac{195}{8} =24 \frac{3}{8}[/tex]
