[tex](1+2+3+...+14):(1+2+3+...+6)= \\ \frac{14*(14+1)}{2}: \frac{6*(6+1)}{2}= \frac{14*15}{2}: \frac{6*7}{2}= \frac{210}{2}: \frac{42}{2}= \frac{210}{2}* \frac{2}{42}= \frac{420}{84} = \boxed{\boxed{5 raspuns \ final} } \\ \\ \\ Pentru \ realizarea \ calculelor \ s-a \ folosit \ formula \ \boxed{\frac{n*(n+1)}{2}= }[/tex]
