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18+10x<5(x+2)+2(x+3) rezolvati inecuatia nr naturale



Răspuns :

[tex]18+10x<5(x+2)+2(x+3)= \\ \\ 18+10x<10x+10+2x+6 \\ \\ 18+10x<12x+16 \\ \\ 10x-12x<16-18 \\ \\ -2x<-2 \\ \\ 2x<2 =>\boxed{x=0}[/tex]