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Aflati solutia ecuatiei [tex] \frac{x+1}{3} + \frac{1}{2} = \frac{1}{6} , [/tex] ∈ Q 


Răspuns :

[tex] \frac{x+1}{3} + \frac{1}{2} = \frac{1}{6} [/tex]
[tex] \frac{2(x+1)}{6} + \frac{3}{6} = \frac{1}{6} [/tex] / ·6 ( înmulțim cu 6).
2x+2 + 3 = 1
2x + 5 = 1
2x = 1 - 5
2x = - 4 x
x = [tex] \frac{-4}{2} [/tex]
= - 2.