[tex]p_{fier}=\dfrac{mg}{S}=\dfrac{\rho Vg}{S}\\ \\ \\ p_{apa}=\dfrac{\rho_0 Vg}{S}[/tex]
Raportul celor doua presiuni se reduce la:
[tex]\dfrac{p_{fier}}{p_{apa}}=\dfrac{\rho}{\rho_0}[/tex]
Date:
[tex]\rho=\text{densitatea fierului}\\ \rho_0=\text{densitatea apei}[/tex]
Spor la calcul.
