Deci, ca sa ma lamuresc, [tex]x+2 = \frac{15}{6}[/tex].
Se rezolva foarte usor.
Aducem la acelasi numitor comun, adica 6.
[tex]x+2 = \frac{x+2}{1} = \frac{6x+12}{6}[/tex]
[tex]\frac{6x+12}{6}=\frac{15}{6} \Rightarrow 6x+12 = 15[/tex]
[tex]\Rightarrow 6x = 15-12 \Rightarrow x =\frac{15-12}{6} = \frac{1}{2}[/tex]
Rezolvare alternativa:
[tex]x+2 = \frac{15}{6} \Rightarrow x = \frac{15}{6}-2 \Rightarrow x = \frac{15}{6} - \frac{12}{6} = \frac{3}{6} = \frac{1}{2}[/tex]
Bonus:
[tex]x-\frac{5}{6} = 0 \Rightarrow x = 0+\frac{5}{6} \Rightarrow x = \frac{5}{6}[/tex]
