3^{38} = 3^{2 x 19} = (3² )^{19} = 9^{19}
2^{59} - 2^{58} - 2^{57} = 2^{57} x ( 2² - 2 - 1) = 2^{57} x 1 = 2^{57} = 2^{ 3 x 19} =
= ( 2³ )^{19} = 8^{19}
deci, se compara 9^{19} cu 8^{19}
cele doua nr. au aceeasi putere (acelasi exponent), dar baze diferite
cum 9 > 8 rezulta ca 9^{19} > 8^{19} deci,
3^{38} > 2^{59} - 2^{58} - 2^{57}
